Given four functions, which one will have the smallest y-intercept? f(x) g(x) h(x) j(x) blake is tracking his savings account with an interest rate of 5% and a original deposit of $6. x g(x) 0 2 1 6 2 10 the function h of x equals 4 to the x power, plus 3 j(x) = 10(2)x

(Updated) g(x). I corrected my math and found out that I missadded g(x). I was explaining y-intercept was your starting point yet I didn't count the starting point for g(x), lol!

Step-by-step explanation:

Looking at the (x)'s, f(x) has a y-intercept of 6. Remember, your y intercept is what you are starting with. Moving on to the next one. g(x), if you do the math, the table goes up by 4. However this isn't the y-intercept. 0 is your starting point, so moving to the side, 2 is next to 0. This makes your y-intercept 2. In the next graph, h(x) (if you have the same one as me) the y-intercept is at 4. On a graph, the Y-intercept is where a point in your x axis meets your y-line. To find your Y-intercept, just go to a graph and mark wherever the line crosses with the y-line as a point. Next one, j(x).  Again, your y-intercept is your starting point. In this equation, your starting number is 10. A way to remember how to spot your y-intercept is this.

f(x) = a (b)^x

Your (x) is your plug in.

Your a is your y-intercept, or starting point.

Your b is your multiplier.

The x is usually the variable, but it can hold an exponet with it.

I'm sorry I'm late still. I understand I edited this so it might not be the best but I did try and correct myself. If there is anyway you can tell me if I'm right please do, again I'm not a math expert tho ^-^

answer:

step-by-step explanation: