Abaseball player throws a ball from the outfield toward home plate. the ball's height above the ground is modeled by the equation y = -16x + 48x + 6,
where y represents height, in feet, and x represents time, in seconds. the ball is initially thrown from a height of 6 feet.
(a) how many seconds after the ball is thrown will it again be 6 feet above the ground?

seconds
(b) what is the maximum height, in feet, that the ball reaches?

feet
by

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

i will pick c put check it over to be sure

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

the answer is 11.2 (i know i’m late)