Casper bought some pencils at .50 each. he had $3 left after the purchase. if he wanted to buy the same number of note pads at .80 each, he would be short 1.50. write a linear equation for the number of pencils he purchased. then solve it.

Required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

Solution:

Let’s assume number of pencils purchased by Casper = x

As given price of each pencil is 0.50 , so price of x pencils = 0.50x = 0.5x

Also given that she was left with $3 after buying x pencils.

So initial amount which was with casper = price of x pencils + amount he was left with.

=> Initial amount with Casper = 0.5x + 3    (1)

Now consider second scenario  

If Casper wanted to buy same number of notepad at price of 0.80 each , then

Total amount need for x notepad = 0.80x = 0.8x

But its also given that he will be short of $1.5.

So initial amount with Casper = 0.80x – 1.5 (2)

On equating initial amount with casper using equation (1) and equation(2) we get

0.5x + 3 = 0.8x – 1.5

=> 0.8x – 0.5x = 3 + 1.5

=> 0.3x = 4.5

=> 0.3x – 4.5 = 0  

=> 3x – 45 = 0

So linear equation for x that is number of pencils he purchased is 3x – 45 = 0 where variable x represents number of pencils.

On solving the linear equation 3x – 45 = 0 for x we get

3x = 45

x = 15

Hence required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1