For how many different digits $n$ is the two-digit number $\underline{6}\underline{n}$ divisible by $n$? (the expression $\underline{6}\underline{n}$ should be interpreted as a two-digit integer with tens digit 6 and units digit $n$, not as 6 times $n$.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

560

hope this : )

the k side

step-by-step explanation:

plese mark mde brainliest!