Create the equation of a cubic in standard form that has a double zero at -2, another zero at 4, and a y-intercept of 16,

f(x) = x³ - 3x - 4

Step-by-step explanation:

Given that x = - 2 has multiplicity 2 and x = 4 are zeros then

(x + 2)² and (x - 4) are the factors of the polynomial and the polynomial is the product of the factors, thus

f(x) = a(x + 2)²(x - 4) ← a is a multiplier

To find a substitute (0, 16) into the equation

16 = a(4)(16), thus

64a = 16

a = =

f(x) = (x + 2)²(x - 4) ← expand factors

    = (x² + 4x + 4)(x - 4)

    = (x³ + 4x² + 4x - 4x² - 16x - 16)

    = (x³- 12x - 16)

   = x³ - 3x - 4

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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