What is the area of a triangle with vertices at (0, – 2), (8, – 2), and (9, 1)?
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units2

ANSWER:  

The area of the triangle with vertices at (0, – 2), (8, – 2), and (9, 1) is 12 square units.

SOLUTION:

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

We know that,

Here in our problem,

Now, substitute the above values in the formula.

Hence, the area of the triangle is 12 sq units.

a. is correct