If zach has 4 times as many dimes as quarters and they have a combined value of 455 cents, how many of each coins does he have?

ANSWER:

Zach has 28 dimes and 7 quarters.

SOLUTION:

Given, Zach has 4 times as many dimes as quarters  

And they have a combined value of 455 cents,  

We need to find how many of each coins does he have?

Let, the number of dimes be x and number of quarters be y.

Then, x = 4y → (1)

Total combined value = 455 cents

x(value of one dime) + y(value of one quarter) = 455 cents

x(10 cents) + x(25 cents) = 455 cents

10x + 25y = 455 → (2)

Now, substitute (1) in (2)

10(4y) + 25y = 455

40x + 25y = 455

65y = 455

y = 7

substitute y value in (1)

x = 4(7)  = 28

Hence, zach has 28 dimes and 7 quarters.

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000