According to the national vital statistics report, vol. 52, no. 10, the probability is 0.6591 that a newborn baby has a birth weight between 6 lbs, 10 oz. and 8 lbs, 13 oz. if 2 newborn babies are randomly selected, what is the probability that at least one of the babies has a birth weight between 6 lbs, 10 oz. and 8 lbs, 13 oz.? assume birth weights of different babies are independent. (use 3 decimal places in your answer)

The required probability is 0.884

Step-by-step explanation:

Consider the provided information.

The probability is 0.6591 that a newborn baby has a birth weight between 6 lbs, 10 oz. and 8 lbs, 13 oz.

The probability that weight is not in between  6 lbs, 10 oz. and 8 lbs, 13 oz is:

1-0.6591=0.3409

We want to find the probability that if 2 babies born then the probability that at least one of the babies has a birth weight between 6 lbs, 10 oz. and 8 lbs, 13 oz.

There are 3 possible case

Case I: If only first baby weight is in between 6 lbs, 10 oz. and 8 lbs, 13 oz.

Case II: If only second baby weight is in between 6 lbs, 10 oz. and 8 lbs, 13 oz.

Case III: If both babies weight is in between 6 lbs, 10 oz. and 8 lbs, 13 oz.

This can be written as:

Hence, the required probability is 0.884

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?