Listed below are systolic blood pressure measurements (mm hg) taken from the right and left arms of the same woman. assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. use a 0.10 significance level to test for a difference between the measurements from the two arms. what can be concluded? right arm 152 138 135 139 132 left arm 178 176 176 142 151

There is a significant difference between the two means based on this samples at the 0.10 level of significance.

Step-by-step explanation:

Let's call

mean of the systolic pressure from the right hand

mean of the systolic pressure from the left hand

and construct a confidence interval for the difference  

based on the sample of size 5.

The confidence interval whose endpoints are

where

= mean of the sample from the right hand

= mean of the sample from the left hand

= standard deviation of the sample from the right hand

= standard deviation of the sample from the left hand

= t-score corresponding to a level of significance 0.10 or a confidence level 90%

Since the sample is too small we have better use the Student's t-distribution with 4 (sample size -1) degrees of freedom, which is the approximation of the Normal distribution for small samples.

For a 90% confidence level equals 2.132

Let's compute now the means and standard deviations of the samples

From the right hand we have

= 139.2

= 7.66

From the left hand we have

= 164.6

= 16.85

Then our confidence interval would be

finally, the interval is

[-43.05, -7.75]

Since our confidence interval does not contain the zero, we can say there is a significant difference between the two means based on this samples at the 0.10 level of significance.

12cm

the answer is d

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752