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Ten times the square of a non-zero number is eqaul to ninety times the number
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Given the sequence 7, 14, 28, 56, which expression shown would give the tenth term? a. 7^10 b. 7·2^10 c. 7·2^9
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Solve: 25 points find the fifth term of an increasing geometric progression if the first term is equal to 7−3 √5 and each term (starting with the second) is equal to the difference of the term following it and the term preceding it.
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3/4 x 1/8 explain how you did it. and you have to flip the fraction like a reciprocal...
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