Mary's kite is flying ablve the beach at the end of a 75-meter string. if the angle of elevation to the kite measures 68° and mary is holding the kite 1.2 meters off the ground, then determine the height of mary's kite flight.

We found h

See figure. The sine trigonometric ratio of the angle 68° is:

sin(68°) = h / 75 multiplied by 75 we get

75xsin(68°) = (h / 75)x75

75xsin(68°) = h resolvemos

69.54 m = h

Then we add 1.2 m with 69.54 m to obtain the height H, i.e.

H= 1.2 +69.54  

H = 70.74 m is the answer.