In a college classroom some chairs are designed for lef-handers. suppose this classroom has 20 chairs, and 8 of them are made for lefies. if 5 students randomly select chairs and sit on them in this classroom, what is the probability that at least 4 of those selected will be seats for lefies?

0.0578

Step-by-step explanation:

Given : Number of chairs = 20

Number of chairs made for lefties =8

Number of chairs made for righties= 20-8=12

Now, total number of way for selecting 5 chairs from 20  =

Number of ways to select at least 4 seats for lefies :-

Now, the probability that at least 4 of those selected will be seats for lefties :-

hence, the required probability = 0.0578

i can't see the picture : /

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!