Assume that there are 14 board members: 9 females, and 5 males including mark. there are 3 tasks to be assigned. note that assigning the same people different tasks constitutes a different assignment.

1) find the probability that both males and females are given a task.

2) find the probability that mark and at least one female are given tasks.

Total members = 14

Total tasks = 3

So, total outcomes =

1) Find the probability that both males and females are given a task.

No. of females = 9

No. of males = 5

Favorable events = 2 female 1 male + 2 male 1 male =

So,  the probability that both males and females are given a task:

=

=

=

So,  the probability that both males and females are given a task is 0.7417

2)Find the probability that Mark and at least one female are given tasks.

Since mark is fixed , so places are left

So, favorable events =  2 female + 1 female 1 male =

So,  the probability that Mark and at least one female are given tasks. :

=  

=  

=  

So, The probability that Mark and at least one female are given tasks is 0.9230

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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