Aspinner and 2 cards are shown below:

a spinner with 7 equal sectors is shown in the figure. the colors green, red, orange, violet, pink, yellow, and blue are marked on it. the arrow points at the red color. two cards are shown on the right side. the colors purple and green are marked on them.

sophie spins the spinner and picks up a card without looking. what is the probability that the spinner stops at red and a green card is selected?

1 over 49
1 over 16
1 over 14
1 over 2

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14

It is given that a spinner and two cards are selected.

A spinner has 7 colors in it:

Green,Red,Orange, Violet, Pink, Yellow, and Blue are marked on it.

Two cards are shown on the right side. The colors Purple and Green are marked on them.

Now we are asked to find the probability that the spinner stops at red and a green card is selected.

Let A  denotes the event that the arrow stops at red.

and B denote the event that a green card is selected.

Now, we have to find:

P(A∩B)

Where P denotes the probability of an event.

As we know that event A and event B are independent.

Hence,

P(A∩B)=P(A)×P(B)

Now,

P(A)=1/7

( Since we have 7 choices out of which only one sector has red color)

Similarly,

P(B)=1/2

( since we have just two cards and one card is green).

Hence,

P(A∩B)=(1/7)×(1/2)=1/14

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14

the answer is 99.

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.