The secretary in exercises 2.121 and 3.16 was given n computer passwords and tries the passwords at random. exactly one of the passwords permits access to a computer file. suppose now that the secretary selects a password, tries it, and—if it does not work—puts it back in with the other passwords before randomly selecting the next password to try (not a very clever what is the probability that the correct password is found on the sixth try?

There is a probability that the correct password is found on the sixth try.

Step-by-step explanation:

We have n passwords, only 1 is correct.

So,

Since a password is put back with other, at each try, we have that:

The probability that a password is correct is

The probability that a password is incorrect is .

There are 6 tries.

We want the first five to be wrong. So each one of the first five tries has a probability of . So, for the first five tries, the probability of getting the desired outcome is .

We want to get it right at the sixth try. The probability of sixth try being correct is .

So, the probability that the first five tries are wrong AND the sixth is correct is:

There is a probability that the correct password is found on the sixth try.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

22

step-by-step explanation: