In △pok pk = ko = 11, m∠k = 145º. find altitude ph.

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5

a reflection across line m

step-by-step explanation:

the first transformation is a 90 degree rotation counterclockwise around the point g. this gets to image gh'j'k'. when the image gh'j'k' is reflected over the line  m the result is g'h"j"k". the final transformation is a reflection over the line  m.