Abc is an isosceles with ab=ac=6cm. if bc=7cm, find angle c.

54.314 °

Step-by-step explanation:

It is given that in triangle ABC, AB = AC = 6m. So, it is an isosceles triangle

Now, it is also given that BC = 7 cm.

We have to find the value of angle C.

If we draw a perpendicular on BC from point A, then it will bisect BC at D i.e. AD is a perpendicular bisector of BC.

Now, the triangle ADC is a right triangle in which, the base DC =7/2 =3.5 cm and hypotenuse AC = 6m (Given) and angle ADC= 90°.

Therefore, Cos∠C = DC/AC =3.5/6.

⇒ ∠C =Cos⁻¹ (3.5/6) =54.314 ° (Answer)

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