Use the process outlined in the lesson to approximate the number 3√10. use the approximation √10 ≈3162 277 7.
. find a sequence of five intervals that contain 3√10 whose endpoints get successively closer to 3√10. write your
iintervals in the form < 3^√10 < 3^s for rational numbers s.

sequence of five intervals

(1) 3³  <   <

(2)  <   <

(3) <   <

(4) <   <

(5)  <   <

Step-by-step explanation:

as per question given data      

√10 ≈ 3.162 277 7    

to find out      

sequence of five intervals

solution      

as we have given that √10 value that is here

√10 ≈ 3.162 277 7           ........................1

so  

when we find           ................2

put here √10 value in equation number  2  

we get     that is  32.27    

so    

sequence of five intervals

(1) 3³  <   <

(2)  <   <

(3) <   <

(4) <   <

(5)  <   <

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.