Solve the equation for xx. for each step, describe the operation used to convert the equation.
3x−[8−3(x−1)]=x+19

x = 6

Step-by-step explanation:

Equation given in the question:

3x − [ 8 − 3(x−1) ] = x + 19

Now,

multiplying the term (3(x-1)) in the equation, we get

⇒ 3x - [ 8 - 3x -3 × (-1)] = x + 19

or

⇒ 3x - [ 8 -3x +3 ] = x + 19

or

⇒ 3x - [ 11 -3x ] = x + 19

now,

multiplying opening the bracket [11 - 3x]

⇒ 3x - 11 - (-3x) = x + 19

or

⇒ 3x - 11 + 3x = x + 19

on adding the terms with same coefficient 'x' on LHS

⇒ (3 + 3)x - 11 = x + 19

or

⇒ 6x - 11 = x + 19

taking -11 to the RHS

⇒ 6x = x + 19 + 11

or

⇒ 6x = x + 30

subtracting x both the sides

⇒ 6x - x = x + 30 - x

or

5x = 30

dividing the both sides by 5

therefore,

x = 6

answer:

the answer is b) divide by -4 on each side and flip the sign.

step-by-step explanation:

we first need to start by dividing. this is because it is a multiplication problem to start.

we also need to make sure we flip the sign because any time you multiply or divide by negative numbers, the sign must be flipped.