Solve the following projectile motion problem.
12. a projectile is launched straight up from ground level with an initial velocity of
400 ft/sec. when will the projectile's height above ground be 2000 ft?

The answer should be 5 seconds. Hope this helps :)

The projectile height is going at a paste of 400 feet a second, so this is concluding that 5 seconds multiply by 400 feet a second is 2000 feet

450

step-by-step explanation:

you get texts and minutes, so why not