By finding the radius of each circle and the distance between their centers, show that the circles x²+y²=4 and x²-4x+y²-4y+4=0 intersect. illustrate graphically.

The circles do intersect.

Step-by-step explanation:

A circle is of the form

(x-h)^2+(y-k)^2=r^2

where,

h = Point on x axis of the circle center

k = Point on y axis of the circle center

So, the center of the circle is at (0,0) and radius is 2 units

The circle center is at the point (2,2) and radius is 2 units.

Hence, the circles do intersect.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32