Mathematics, 22.10.2019 02:00 nicolascorrea0207

Let μ=e(x), σ=standard deviation of x. find the probability p(μ-σ ≤ x ≤ μ+σ) if x has a geometric distribution with p = 0.61. round your answer to 4 decimal places.

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Answer from: MartinTDL

P(μ-σ ≤ X ≤ μ+σ) = 0.61 + 0.1275 = 0.7375

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

p = 0.61 .

$\mu = \frac{1-p}{p} = 0.6393$

$\sigma = \sqrt{\frac{1-p}{p^{2}} = 1.0234$

P(μ-σ ≤ X ≤ μ+σ) = $P(-0.3841 \leq X \leq 1.6627) = P(0 \leq X \leq 1.6627) = f(0) + f(1.6627)$

$f(x) = (1-p)^{x}p$

$f(0) = (0.39)^{0}(0.61) = 0.61$

$f(1.6627) = (0.39)^{1.6627}(0.61) = 0.1275$

P(μ-σ ≤ X ≤ μ+σ) = 0.61 + 0.1275 = 0.7375

Answer from: Quest

i think the answer is fried chicken ; >

step-by-step explanation:

Answer from: Quest

a. we have two

lines: y = 4-x and

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b. 4-x = 8-x^-1

x 4-x 8-x^-1

-3 7

8.33

-2 6 8.5

-1 5 9

0 4

1 3

2 2

7.5

3 1 7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:

x=-4.236

y = 4-x = 4 – (-4.236)

= 8.236

y = 8-x^-1 = .236)^-1

= 8.236

x=0.236

y = 4-x = 4 – (0.236) = 3.764

y = 8-x^-1 = 8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c. to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x and y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines. the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

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Let μ=e(x), σ=standard deviation of x. find the probability p(μ-σ ≤ x ≤ μ+σ) if x has a geometric di...

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