Describe the discontinuity for the function f(x)= (x^2 + 9)/(x-3)
a. there is a removable discontinuity at x=3
b. there is a hole at x= -9
c. there is a vertical asymptote
d. there is no discontinuity at x =3

i need the work to be shown so that i understand how you did.

Start by factoring the numerator and denominator of the function. A point of discontinuity occurs when a number is both a zero of the numerator and denominator. Since is a zero for both the numerator and denominator, there is a point of discontinuity there. To find the value, plug in into the final simplified equation. Hope this helps.. :D

Step-by-step explanation:

i need more information

step-by-step explanation:

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