Suppose we have a quadratic equation ax²+bx+c=0 so that a+c=0.does the quadratic equation have one solution or two distinct solutions? are they real or complex? explain how you know.

The roots of equation are real and distinct.

Step-by-step explanation:

Given that

ax²+bx+c=0

a+c=0

To find the behavior of roots we have to find out D

If

D> 0  Two real distinct roots

D=0  Two equal roots

D<0 Tow imaginary  roots

a+c=0

a= - c

It means that D>0 .So the roots of equation is real and distinct.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

what are ur choices?