Is it possible that the quadratic equation ax²+bx+c=0 has a positive real solution if a, b and c are all positive real numbers?

Not possible

Step-by-step explanation:

supposing both the roots as α and β and a,b and c are all positive real numbers.

Then α+β= -b/a which will be negative

⇒ α+β<0

and αβ= c/a , which will positive

⇒αβ>0

also, -b/a>0 and c/a<0

⇒b/a<0 and c/a<0  which is not possible because all a, b and c are positive real numbers.

hence, it is not possible that the quadratic equation ax²+bx+c=0 has a positive real solution if a,b and c are all positive real numbers

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: