Is it possible that the quadratic equation ax²+bx+c=0 has a positive real solution if a, b and c are all negative real numbers?

yes

Step-by-step explanation:

Given

a,b,c<0

For quadratic equation to have real roots Discriminant should be greater than zero

D>0

Thus

b is negative so its square is positive

a & c is negative so their product is positive

so Discriminant is Positive when

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)