Use the fact that x⁴+64=(x²-4x+8)(x²+4x+8) to explain how you know that the graph of y=x⁴+64 has no x-intercepts. you need not find the solutions.

The term for (x²-4x+8) and for (x²+4x+8) is negative.

Step-by-step explanation:

The x intercepts are the values of x in which the function is equal to zero. So if x⁴+64=(x²-4x+8)(x²+4x+8), the x intercepts are the values of x that satisfy:

(x²-4x+8) = 0 or (x²+4x+8) = 0

Then, the values of x that satisfy (ax²+bx+c) = 0 are calculated as:

or

So, if the term is negative the graph of the function has no x-intercepts.

Then, for (x²-4x+8) = 0, we get:

At the same way, for (x²+4x+8) = 0, we get:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

idk man good luck man