The city council is planning a new city park on a triangular plot of land
formed by three intersecting streets.
the designer placed the triangle on a grid to determine the side lengths and
angle measures needed for the purchase and placement of a fence
surrounding the park. each unit on the grid is one inch, which represents
20 feet of actual length.
the measure of angle cab in the designer’s diagram is (5x + 1)°, and the
measure of angle acb is (3x + 12.5)°.

create a report that provides a detailed
description of the park. include the following in your report:
• the actual side lengths of the triangular plot of land
• the type of triangle formed by the intersection of the three streets
• the amount of fencing needed to surround the city park
• the actual measure of each angle of the triangle

AB = AC = 172.2 feet , CB = 200 feet

Isosceles triangle

Perimeter of the park = 544.4 feet

∠CAB = 71° , ∠ACB = ∠ABC = 54.4°

Step-by-step explanation:

stan loona luv

b i think

step-by-step explanation:

not really sure

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.