Asteamer going downstream traveled the distance between two ports in 3 hours. the return trip took 3 hours 40 minutes. find the speed of the water current if the speed of the steamer in still water is 18 mph.

A steamer going downstream traveled the distance between two ports in 3 hours. The return trip took 3 hours 40 minutes. Find the speed of the water current if the speed of the steamer in still water is 18 mph.

distance = D

return trip time (RT) = 3 hours 40 minutes.

speed of the water current = VW

steamer speed (SS) =  18 mph

direct trip time (DT) = 3 hours

D = DT x (18 + VW) = 3(18 + VW) = 54 + 3VW

D = RT x (18 -VW) = 3.666 x (18 - VW) = 66 - 3.666VW

54 + 3VW = 66 - 3.666VW

3VW + 3.666VW = 66 - 54

6.666VW = 12

VW = 1. 8 mph

it should be a and d. lmk if i'm wrong xd

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3