7x+4y=5 find the slope of a line parallel and perpendicular

To find the slope of a line parallel, you must firs of all make y the subject of the formula i.e

subtract 7x from both side of the equation

which implies : 7x -7x+4y = 5 - 7x

                      so,           4y = 5 - 7x

Divide both side by 4, since you are to make y to stand alone

This implies                    y = 5/4  - 7x/4.

Recall: If M1 represent a slope and M2 represent another slope, if they are parallel , then M1 = M2 and if they are perpendicular, then M1 = -1/M2

SO, the slope parallel = -7/4

And the slope perpendicular = -1 divided by -7/4

which implies                          -1 x -4/7

                                                 = 4/7

Step-by-step explanation:

Step-by-step explanation:

7x+4y=5

     4Y = -7X +5

       y = -7/4x + 5/4

Slope m₁ =-7/4

Slope of the line parallel to this line m₂ = -7/4

Slope (m₃) of the line perpendicular to this line   m₃= 4/7

  m₁  * m₃ = -1

 -7/4 * m₃  = -1

         m₃  = -1 * (-4/7) = 4/7

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

yes

step-by-step explanation: