Aresearcher records the following time spent sleeping per night (in hours) in a group of participants: 5.8 ± 1.8 (m ± sd). the researcher decides to categorize participants who sleep between 6 and 8 hr as moderate sleepers. what percentage of participants fell in this category?

 40.68 %

Step-by-step explanation:

We need  to find the interval between the values 0.2 and 2.2

 0.2 ≤ z ≤ 2.2  

Since in the standardized normal curve the mean 5.8 will be 0

Area for z values ≥ 0.2        ⇒    0.0793  and  area for z ≤ 2.2

area between 0 and 0.2 is 0.0793 ;  and area between 0 to 2.2  is 0.4861

this last value includes the previous value at the left of  z = 0.2

As we are looking for participants in the interval   0.2 ≤ z ≤ 2.2 we need to subtract  areas 0.4861 - 0.0793 = 0.4068 express in % is 40.68 %

the answer is b.)

< 1=< 2

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: