Fish story: according to a report by the u. s. fish and wildlife service, the mean length of six-year-old rainbow trout in the arolik river in alaska is 478 millimeters with a standard deviation of 38 millimeters. assume these lengths are normally distributed. round the answers to at least two decimal places. (a) find the 54th percentile of the lengths.

11.29.

Step-by-step explanation:

We are given that The mean length of six-year-old rainbow trout in the Arolik River in Alaska is 478 millimeters with a standard deviation of 38 millimeters.

We are also given that these lengths are normally distributed.

So, The highest value is at mean .(Refer the attached figure).

Formula :

The 54th percentile of the lengths is 11.29.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts