Asimple random sample was taken of 44 water bottles from a bottling plant’s warehouse. the dissolvedoxygen content (in mg/l) was measured for each bottle, with these results: 11.53, 8.35, 11.66, 11.54, 9.83, 5.92, 7.14, 8.41, 8.99, 13.81, 10.53, 7.4, 6.7, 8.42, 8.4, 8.18, 9.5, 7.22, 9.87,6.52, 8.55, 9.75, 9.27, 10.61, 8.89, 10.01, 11.17, 7.62, 6.43, 9.09, 8.53, 7.91, 8.13, 7.7, 10.45, 11.3, 10.98, 8.14,11.48, 8.44, 12.52, 10.12, 8.09, 7.34here the sample mean is 9.14 mg/l. the population standard deviation of the dissolved oxygen content for the warehouse is known from longexperience to be aboutσ= 2 mg/l.1 (a) find a 98% confidence interval for the unknown population mean dissolved oxygen content.(b) interpret your interval.(c) what sample sizenis required to get a 98% confidence interval with error margin 0.5?

a) (8.4375,9.8425)

b) 87

Step-by-step explanation:

We are given the following data-set.

11.53, 8.35, 11.66, 11.54, 9.83, 5.92, 7.14, 8.41, 8.99, 13.81, 10.53, 7.4, 6.7, 8.42, 8.4, 8.18, 9.5, 7.22, 9.87,6.52, 8.55, 9.75, 9.27, 10.61, 8.89, 10.01, 11.17, 7.62, 6.43, 9.09, 8.53, 7.91, 8.13, 7.7, 10.45, 11.3, 10.98, 8.14,11.48, 8.44, 12.52, 10.12, 8.09, 7.34

n = 44

Sample Mean = 9.14 mg per Litre

Population Standard Deviation = 2 mg per Litre

a) Formula:

Confidence interval:

Putting the values, we get,

b) Thus, it could be said that above interval gives about 98% confidence that it will contain the true value of mean of the dissolved oxygen content for the warehouse.

c) Margin of error

Thus, a sample size of 87 is  required to get a 98% confidence interval with error margin 0.5.

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.