Arectangle has a perimeter of 56 in. the length is four more than the width. what are the length and width of the rectangle

Width = 12 in

Length = 16 in

Step-by-step explanation:

Let, the Width of the rectangle = w in

Now, the length of the rectangle = (w + 4) in

Now, Perimeter = 56 in

Also, we know that

Perimeter of the Rectangle = 2 (Length +Width)

or, 2 (Length +Width) = 56

⇒ 2(w + 4 +w) = 56

or, 4w =56 -8

width  = 12 in

So, Length = w + 4 = 12 + 4 = 16 in

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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