One container holds 1 1/7 quarts of water and second container holds 5 3/4 quarts of water how many more harts of water does the second container hold then the first

129/28 (4.6 approx.)

Step-by-step explanation:

The first hols 1 1/7 quarts, it is: 1 + 1/7

Using 7 as common denominator and summing:

1 + 1/7 = 7/7 + 1/7 = 8/7

The second holds 5 3/4 which is: 5 + 3/4. Using 4 as common denominator:

5 + 3/4 = 20/4 + 3/4 = 23/4

Now we need to know how much greater is 23/4 than 8/7. For comparing them we need to set them to a common denominator. The easiest way is use a number that is multiple of both, 4 and 7, lets us 28. We need to multiply the numerators by the number that, multiplied by denominators gives us 28. For the first is 4, and for the second 7.

8/7 = (8*4)/7*4=32/28

23/4= (23*7)/4*7 = 161/28

Now, we only have to subtract:

23/4 - 8/7 = 161/28 - 32/28 = 129/28

So, the second container has 129/28 more quarts of water (approx. 4.60) than the first.

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step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic