The perimeter of a rectangle is 82 units. 'what are the dimensions of a rectangle if
the length is 2x - 8 and the width is 6x+1
(need answers asap! )

L = 2*6 - 8 = 12 - 8 = 4

W = 6*6 + 1 = 36 + 1 = 37

That's the math.

Step-by-step explanation:

P = 2*(L + W)

L = 2x - 8

W= 6x + 1

P = 82

2(2x - 8 + 6x+1) = 82     Combine terms in the brackets.

2(8x - 7) = 82                 Divide both sides by 2

2(8x - 7)/2 = 82/2

8x - 7 = 41                       Add 7 to both sides

8x - 7 +7 = 41+7

8x = 48                           Divide by 8

8x/8 = 48/8

x = 6

the answer is d. 75%

if i put something wrong your not gonna like it so rather not say nothing.