Roland has three paperback books in for hard cover books. each hard cover book is worth $11 more than each paper back book. if the value of all his books is $79 what is the cost of one paper back book? right and solve an equation to find your solution.

answer: the common difference is -0.10

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

if e is the midpoint of bd, then bd is 14.

step-by-step explanation: