An airline has sold 560 tickets for a certain flight (with capacity 555 seats) in the assumption that not all passengers that purchased a ticket will arrive for the flight. assume that the probability that a passenger will not show up for the flight is 1%, independently of all other passengers. how likely is it that there are more passengers showing up for the flight than seats are available? calculate this probability by using a binomial distribution for the number of passengers that showed up for the flight.

There is a 34.09% probability that there are more passengers showing up for the flight than seats are available.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And is the probability of X happening.

For this problem,

There are 560 tickets, so

There is a 1% probability that a passenger will not show up for the flight, so

How likely is it that there are more passengers showing up for the flight than seats are available?

An airline has sold 560 tickets for a certain flight (with capacity 555 seats).

So, this question is: What is the probability that at most 4 passengers do not show up for the flight.

So

There is a 34.09% probability that there are more passengers showing up for the flight than seats are available.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb