Consider a sampling distribution with p equals 0.12 and samples of size n each. using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion.
(a) for a random sample of size n equals 5000.
(b) for a random sample of size n equals 1000.
(c) for a random sample of size n equals 500.

Consider a sampling distribution with p equals 0.12 and samples of size n each.

Then, formula for mean = p

Formula for standard deviation=

(a) For a random sample of size n equals 5000.

Mean = 0.12

Standard deviation=

(b) For a random sample of size n equals 1000.

Mean = 0.12

Standard deviation=

(c) For a random sample of size n equals 500.

Mean = 0.12

Standard deviation=

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72