Roland has 3 paperback books and 4 hardcover books. each hardcover book is worth $11 more than each paperback book. if the value of all of his books is $79, what is the cost of one paperback book?

$5

Step-by-step explanation:

Let cost of paperback book be "p"

and

Cost of hardcover book be "h"

Each hardcover is $11 more than each paperback, thus we can write:

h = p + 11

3 paperbacks at "p" each and 4 hardcovers at "h" each totals 79, thus we can write:

3p + 4h = 79

We can now put the 1st equation in 2nd equation and find "p" (cost of paperback book). Shown below:

Hence, each paperback book costs $5

mx+89b(-98)nb

step-by-step explanation:

my guess would be b and d, but i didn’t actually get out the pen and paper. lol