The administrator of a nursing home would like to do a time-and-motion study of staff time spend per day performing nonemergency tasks. prior to the introduction of some efficiency measures, the average number of person-hours per day spent on these task was 휇=16. the administrator wants to test whether the efficiency measures have reduced the value of 휇. how many days must be sampled to test the proposed hypothesis if she wants a test having 훼=0.05and the probability of type ii error of at most 0.1 when the actual values of 휇is 12 hours or less? assume 휎=7.64

32 days must be sampled to test the proposed hypothesis.

Step-by-step explanation:

Consider the provided information.

The average number of person-hours per day spent on these task was .

The actual value of μ is 12 hours or less i.e μ=12

She wants a test having α=0.05

The probability of a type II error of at most β=0.10 and σ=7.64.

δ = μ-μ0

   = 12-16

  = -4

Now use the formula for calculating the sample size:

Substitute the respective values.

Hence, 32 days must be sampled to test the proposed hypothesis.

step-by-step explanation: the answer for wha if rt is 10 centimeters long, and wha is st? it’s 6