Given that z is a standard normal random variable, find z for each situation (to 2 decimals).

a. the area to the left of z is .9738

b. the area between 0 and z is .4738 ( is positive).

c. the area to the left of z is .8531

d. the area to the right of z is .1251

e. the area to the left of z is .6700

f. the area to the right of z is .3300

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

a - base

b - exponent

so,

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

nope.   happens to me as well.

-aparri