You are playing a dice game. the object of the game is to roll a certain combination of numbers in a single toss of two dice. your dice are 'fair', but your opponent likes to win, and his dice are 'loaded' such that a four has a 7/36 probability of landing upwards. that means that the opposite side of four is counter-loaded (the opposite sides of a die adds to seven). what is the probability of your opponent rolling two even numbers? give your answer as a decimal value, not a percent.

There is a 0.2785 probability of your opponent rolling two even numbers.

Step-by-step explanation:

Since we are looking for the probability of rolling even numbers, we must consider the odds of rolling a 2, a 4 or a 6.

A fair dice would yield in a 6/36 chance of rolling each number, but since these dice are loaded, there is a 7/36 chance of rolling a 4 and a 5/36 chance of rolling a 3 (opposite side of 4); the probabilities for rest remain the same.

Therefore, the probability (P1) of rolling and even number in one die is:

Since the game involves two dice, the probability of rolling even numbers on both is:

There is a 0.2785 probability of your opponent rolling two even numbers.

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step-by-step explanation:

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40