Given: m zade = 60° and m 2cdf = (3x + 15)
prove: x = 15
what is the missing statement and the missing reason in
step 5?
statements
reasons
1. mzade -60°
1. given
mzcdf-(3x+15)
2. zade and zcdf are vert. zs 2. def. of vert. zs
3. zade - cdf
3. vert. zs
4. mzade = m2cdf
4. def. of
5. ?
15. ?
6. 45 - 3x
| 6. subtr. prop.
7. 15-x
| 7 div. prop
(3x + 15)
statement: 60 = 3x + 15; reason: substitution
statement: x = 15; reason: subtraction property of
equality
statement: 60 = 3x + 15; reason: transitive property
statement: x = 15; reason: subtraction and division
properties of equality

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

idk

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

113.42

i hope that is right.

step-by-step explanation: