Arectangular garden is 6 feet long and 4 feet wide. a second rectangular garden has dimensions that are double the dimensions of the first garden. what is the percent of change in perimeter from the first garden to the second garden?

__________         _____________________
|    6 feet      |        |    6 feet       |     6 feet      |
|                   |        |                    |                    |    4 feet
|_________ |        |__________|__________|
                             |                    |                    |
                             |                    |                    |    4 feet
                             |__________|__________|

the figure shows that the second garden has a circumference twice . We must , however, prove.
Denote the sides of the first garden - a rectangle letters a and b
circuit garden
C₁ = 2a + 2b = 2*(a+b)
The sides of the second garden also denoted with the letters a and b . We calculate the circuit
C₂ = 2*2a + 2*2b = 4a + 4b = 4*(a+b)


 
2 = 2*100%=200%
200% -100% = 100%

Answer : The ratio of the second garden to the first ( ratio ) is 2 . Circuit increased by 100 %

The answer should be 5.