Assuming a 4% (0.04) interest rate, $300 invested today in a savings account today will be worth $312 in one year. what will that amount be in 2 and 3 years, and what is the total interest you will earn at the end of three years.

in 2 years the savings account will show: $324.48

in 3 years the savings account will show: $337.46

so the interest earned in these three years would be $337.46 - $300 = $37.46

Step-by-step explanation:

The equation for interest rate compounded annually is what describes this investment, since: where A is the accrued value (total value of principal plus accumulated interest) in the account after the first year ($312), P the principal ($300 in our case), and r the interest rate in decimal form (0.04), and t is the time in years (one for the fist year). They perfectly satisfy the equation:

Then, we can apply this equation for years 2 and 3, just changing the value of t to 2 and 3, as shown below:

We can round the last value to two decimals (cents) obtaining: $337.46

The pure interest after the three years is therefore the total at that time minus the principal the account was started with ($300): $337.46 - $300 = $37.46

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.