The equation (y-y1)=m(x-x1) represents the point-slope form of a linear equation. which equation can be used to find y1?

y1 = m(x – x1) + y

y1 = -mx + mx1 – y

y1 = y – mx + mx1

y1 = -mx – mx1 + y

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

step-by-step explanation:

mrbilldoesmath!

answer: a parabola

steps:

(x-1)(x+4)   = x(x+4) - 1(x+4) = (x^2 + 4x) - (x+4)

                = x^2 +4x -x -4   = x^2 +3x -4

which is a parabola

mrb