Suppose that 50% of the subscribers of a cable television company watch the shopping channel at least once a week. the cable company is trying to decide whether to replace this channel with a new local station. a survey of 100 subscribers will be undertaken. the cable company has decided to keep the shopping channel if the sample proportion is greater than 0.585. what is the approximate probability that the cable company will keep the shopping channel, even though the true proportion who watch it is only .50? (round the answer to four decimal places.)

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

step-by-step explanation:

for the free

wait nvm i know the correct answer now its 100%   81 square feet

~batmans wife dun dun