If a is inversely proportional to b/2 and a = 1 when b = 10, then what is the value of a when b = 35? a1. 1/7 a2. 1/5 a3. 2/9 a4. 9/4 a5. 2/7

A5 .  

Step-by-step explanation:

Given in ques as a inversely proportion to b/2

it can be written as a∝

Now we put a proportionality constant (k) here

so, a=k

or  a=

    Now for a= 1   and b= 10

1=

10= 2k

or,k=5

Now agin for b= 35 and take k value as 5, we get a value

a=

so, a=    Answer

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

i think it might be a but you might want a second opinion