Pforword q is true an and q is true, then p is true sometimes always or never

Explanation:

The statement is P forward Q is true and q is true, then p is true sometimes always or never.

That, written using logical symbology, is:

p → q is known as a conditional statement.

When the conditional p → q is true and p is also verified to be true, you must conclude that q is (necessarily) true (else the conditional would be false).

That also means that if q is verified to be false (not true), p must necessarily be false (else the conditional would be false).

Nevertheless, the fact that q is true, does not permit to conclude whether p is true or false: p can be either true or false when you only know that q is true.

Then, you cannot tell that p is true always or never; some times it could be true and others false.

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step-by-step explanation:

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simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .